Excel 2002 SP3
Win XP Pro SP2

*Follow-up to: microsoft.public.excel*

Hi,
I have an IF formula where =IF(LEFT(D3,3)="ABc",(B3*C3)/50,B3*C3)
When LEFT(D3,3)="ABC", unfortunately, it seems XL does not see the
difference between the lower case "c" in former example and upper case
"C" in latter example.
Is it me?
Can I get around this?

Use the EXACT() function

--
Kind regards,

Niek Otten
Microsoft MVP - Excel

"stef" <(E-Mail Removed)> wrote in message news:%23TzKv$(E-Mail Removed)...
| Excel 2002 SP3
| Win XP Pro SP2
|
| *Follow-up to: microsoft.public.excel*
|
| Hi,
| I have an IF formula where =IF(LEFT(D3,3)="ABc",(B3*C3)/50,B3*C3)
| When LEFT(D3,3)="ABC", unfortunately, it seems XL does not see the
| difference between the lower case "c" in former example and upper case
| "C" in latter example.
| Is it me?
| Can I get around this?

Perhaps I should add the D3 is the result of a formula in same cell so
it may be creating this problem?
Is the use of INDIRECT indicated perhaps?

stef wrote:
> Excel 2002 SP3
> Win XP Pro SP2
>
> *Follow-up to: microsoft.public.excel*
>
> Hi,
> I have an IF formula where =IF(LEFT(D3,3)="ABc",(B3*C3)/50,B3*C3)
> When LEFT(D3,3)="ABC", unfortunately, it seems XL does not see the
> difference between the lower case "c" in former example and upper case
> "C" in latter example.
> Is it me?
> Can I get around this?

On Thu, 06 Dec 2007 16:35:32 -0500, stef <(E-Mail Removed)> wrote:

>Excel 2002 SP3
>Win XP Pro SP2
>
>*Follow-up to: microsoft.public.excel*
>
>Hi,
>I have an IF formula where =IF(LEFT(D3,3)="ABc",(B3*C3)/50,B3*C3)
>When LEFT(D3,3)="ABC", unfortunately, it seems XL does not see the
>difference between the lower case "c" in former example and upper case
>"C" in latter example.
>Is it me?
>Can I get around this?


=IF(EXACT("Abc",LEFT(D3,3)),(B3*C3)/50,B3*C3)


--ron

Thanks.
Actually, come to think of it, if I could have a formula that does if 3
letter of D3 is lower case, then divide by 50--that would be the best.
Is there a way to define "lower case" in 3rd position?

Niek Otten wrote:
> Use the EXACT() function
>

Thanks

Ron Rosenfeld wrote:
> On Thu, 06 Dec 2007 16:35:32 -0500, stef <(E-Mail Removed)> wrote:
>
>> Excel 2002 SP3
>> Win XP Pro SP2
>>
>> *Follow-up to: microsoft.public.excel*
>>
>> Hi,
>> I have an IF formula where =IF(LEFT(D3,3)="ABc",(B3*C3)/50,B3*C3)
>> When LEFT(D3,3)="ABC", unfortunately, it seems XL does not see the
>> difference between the lower case "c" in former example and upper case
>> "C" in latter example.
>> Is it me?
>> Can I get around this?
>
>
> =IF(EXACT("Abc",LEFT(D3,3)),(B3*C3)/50,B3*C3)
>
>
> --ron

=IF(EXACT(MID(A1,3,1),LOWER(MID(A1,3,1))),"lower", "upper")

--
Jim
"stef" <(E-Mail Removed)> wrote in message
news:%(E-Mail Removed)...
| Thanks.
| Actually, come to think of it, if I could have a formula that does if 3
| letter of D3 is lower case, then divide by 50--that would be the best.
| Is there a way to define "lower case" in 3rd position?
|
| Niek Otten wrote:
| > Use the EXACT() function
| >

Thanks

Jim Rech wrote:
> =IF(EXACT(MID(A1,3,1),LOWER(MID(A1,3,1))),"lower", "upper")
>

You could use something like this:

=IF(CODE(MID(D3,3,1))<=90,"Upper","Lower")

Where you'd replace "Upper" with what you want it to do if the 3rd character
is upper case and replace "Lower" with what you want it to do if the 3rd
character is lower case.
This assumes that the 3rd character will always be an alpha character (no
numbers or special symbols) and that your computer is using standard ASCII
character set.

Hope that helps.
--
Mike Lee
McKinney,TX USA


"stef" wrote:

> Thanks.
> Actually, come to think of it, if I could have a formula that does if 3
> letter of D3 is lower case, then divide by 50--that would be the best.
> Is there a way to define "lower case" in 3rd position?
>
> Niek Otten wrote:
> > Use the EXACT() function
> >
>

That's good, (only letters no numbers or symbols in 3rd position). I
will try it. Tx.

mikelee101 wrote:
> You could use something like this:
>
> =IF(CODE(MID(D3,3,1))<=90,"Upper","Lower")
>
> Where you'd replace "Upper" with what you want it to do if the 3rd character
> is upper case and replace "Lower" with what you want it to do if the 3rd
> character is lower case.
> This assumes that the 3rd character will always be an alpha character (no
> numbers or special symbols) and that your computer is using standard ASCII
> character set.
>
> Hope that helps.