Counting specific text in a cell

[Steve]

The following info is imported into one cell.

P5-MPC FT 81,
P5-MPC FT 82,
P5-MPC FT 83,
P5-MPC FT 93,
P6-PPDMO PTF 4,
P6-PPDMO PTF 16

I need to count how many FT's are in the cell, and how many PTF's are in the
cell. The above data will vary in different cells, with up to a combination
of possibly 15 total FT's & PTF's in the various cells.

Thanks,

Steve

 

[JulieD]

Hi Steve

you can use the COUNTIF function
=COUNTIF(A1:A10,"* FT *")
=COUNTIF(A1:A10,"* PTF *")

Cheers
JulieD

 

[Steve]

I did try countif, but could not get it to work.
The information is all in one cell, in this case D35.

=COUNTIF(D35,"* FT *")

This formula is resulting in 1, not 5.

Thanks,

Steve

 

[JulieD]

Hi Steve

sorry missed the bit about it all being imported into one cell - any chance
you can use data / text to columns to split it up into mulitple cells? if
not, hopefully someone else will have an idea on how to do this.

Cheers
JulieD

 

[JulieD]

Hi Steve

actually, i had another think about it and these formulas should work:
=(LEN(D35)-LEN(SUBSTITUTE(D35," FT ","")))/4
=(LEN(D35)-LEN(SUBSTITUTE(D35," PTF ","")))/5

Cheers
JulieD

 

[Steve]

I wouldn't know where to begin for that one either, and am guessing it would
be much more efficient if I could keep that data in that one cell, especially
when the various cells ( up to hundreds) may have up to 15 incidents of the
FT & PTF in each cell.

Steve

 

[Myrna Larson]

I think JulieD missed the fact that the text is all in one cell. Try it this
way. Let's assume the text you are looking for (FT or PTF) is in C35

=(LEN(D35)-LEN(SUBSTITUTE(D35,C35,"")))/LEN(C35)

BTW, the formula is case-sensitive. You have to search for FT, not ft or fT,
etc.

 

[Steve]

Julie & Myrna,

Thank you both. It works great.

Steve