Actual open a file using a Filedialog box

D

Dave K.

I have the following code in the on click event procedure for a toggle button
in access 2003.

Dim dlgOpen As FileDialog

Set dlgOpen = Application.FileDialog(DialogType:=msoFileDialogOpen)

With dlgOpen
.AllowMultiSelect = True
.Show
End With

End Sub

I want to actually open a file when I clck the open button in the dialog box
not return the file file path
 

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