Bandwidth

G

Guest

I am in the early stage of hosting my own sites on a Win 2003 server. I know
the general things in preparation for this but know nothing about allocating
enough bandwidth to insure that visitors are not slowed down by my set up. I
have checked everything as best I can but don't know very much about the
various providers and offerings they may have currently. I want to start
with enough bandwidth which seems to be about 384kb down. Does anyone know a
formula for determining the correct amount based on the number of hits or
visitors?
 
R

Ronx

I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast as I
download, it is slow and will hold me up. Now multiply that by the forecast
number of simultaneous visitors to the sites and you have some idea of the
bandwidth requirements. In practice, some visitors will be using broadband,
some dialup, so there is some averaging to do here. IMO 384kb is only
suitable for a few simultaneous dialup customers - and remember you are
uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per second)
with overheads.
 
G

Guest

Thanks for your answer Ron. I said in error download when I meant upload. It
is my upload speed that is 384kb. Not lets see if I can divide correctly. At
60kb per page (average) visitors could download 6.4 pages per second
simultaneously. Is that correct? If so, maybe that is enough to start and I
could get more if necessary.


Ronx said:
I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have some
idea of the bandwidth requirements. In practice, some visitors will be
using broadband, some dialup, so there is some averaging to do here. IMO
384kb is only suitable for a few simultaneous dialup customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


I am in the early stage of hosting my own sites on a Win 2003 server. I
know the general things in preparation for this but know nothing about
allocating enough bandwidth to insure that visitors are not slowed down by
my set up. I have checked everything as best I can but don't know very
much about the various providers and offerings they may have currently. I
want to start with enough bandwidth which seems to be about 384kb down.
Does anyone know a formula for determining the correct amount based on the
number of hits or visitors?
 
J

Jens Peter Karlsen[FP MVP]

If the speed is 60KB per second then he could download 1 page that is
60KB in one second. However you can only deliver a little over half of
that speed so 1.5 second would be more like it as long as there is no
other traffic.

Regards Jens Peter Karlsen. Microsoft MVP - Frontpage.
-----Original Message-----
From: anon [mailto:anon]
Posted At: 25. oktober 2004 15:51
Posted To: microsoft.public.frontpage.programming
Conversation: Bandwidth
Subject: Re: Bandwidth


Thanks for your answer Ron. I said in error download when I
meant upload. It is my upload speed that is 384kb. Not lets
see if I can divide correctly. At 60kb per page (average)
visitors could download 6.4 pages per second simultaneously.
Is that correct? If so, maybe that is enough to start and I
could get more if necessary.


Ronx said:
I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast as
I download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have some
idea of the bandwidth requirements. In practice, some visitors will be
using broadband, some dialup, so there is some averaging to do here.
IMO 384kb is only suitable for a few simultaneous dialup customers -
and remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message news:%[email protected]...
I am in the early stage of hosting my own sites on a Win 2003 server.
I know the general things in preparation for this but know nothing
about allocating enough bandwidth to insure that visitors are not
slowed down by my set up. I have checked everything as best I can but
don't know very much about the various providers and offerings they
may have currently. I want to start with enough bandwidth which seems to be about 384kb down.
Does anyone know a formula for determining the correct amount based on
the number of hits or visitors?
 
R

Ronx

Is that 384K bits or Bytes? If it's 384K bits then, as Jens remarked, you
are not delivering as fast as I can download (512K bits/second). You could
serve 6 dialup customers, but anyone on broadband will find your server
slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload speed), then
you are on your way. Upload and download speeds are normally expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


Thanks for your answer Ron. I said in error download when I meant upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4 pages
per second simultaneously. Is that correct? If so, maybe that is enough to
start and I could get more if necessary.


Ronx said:
I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have some
idea of the bandwidth requirements. In practice, some visitors will be
using broadband, some dialup, so there is some averaging to do here. IMO
384kb is only suitable for a few simultaneous dialup customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


I am in the early stage of hosting my own sites on a Win 2003 server. I
know the general things in preparation for this but know nothing about
allocating enough bandwidth to insure that visitors are not slowed down
by my set up. I have checked everything as best I can but don't know very
much about the various providers and offerings they may have currently. I
want to start with enough bandwidth which seems to be about 384kb down.
Does anyone know a formula for determining the correct amount based on
the number of hits or visitors?
 
G

Guest

It is 384k bytes per second. Sorry if I confused anyone. This is another new
area for me. Is my math correct that 6.4, 60kb pages could be downloaded
simutaneously per second then?


Ronx said:
Is that 384K bits or Bytes? If it's 384K bits then, as Jens remarked, you
are not delivering as fast as I can download (512K bits/second). You
could serve 6 dialup customers, but anyone on broadband will find your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload speed), then
you are on your way. Upload and download speeds are normally expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


Thanks for your answer Ron. I said in error download when I meant upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4 pages
per second simultaneously. Is that correct? If so, maybe that is enough
to start and I could get more if necessary.


Ronx said:
I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have some
idea of the bandwidth requirements. In practice, some visitors will be
using broadband, some dialup, so there is some averaging to do here.
IMO 384kb is only suitable for a few simultaneous dialup customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message I am in the early stage of hosting my own sites on a Win 2003 server. I
know the general things in preparation for this but know nothing about
allocating enough bandwidth to insure that visitors are not slowed down
by my set up. I have checked everything as best I can but don't know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to be about
384kb down. Does anyone know a formula for determining the correct
amount based on the number of hits or visitors?
 
S

Steve Easton

In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
........................with a computer

It is 384k bytes per second. Sorry if I confused anyone. This is another new
area for me. Is my math correct that 6.4, 60kb pages could be downloaded
simutaneously per second then?


Ronx said:
Is that 384K bits or Bytes? If it's 384K bits then, as Jens remarked, you
are not delivering as fast as I can download (512K bits/second). You
could serve 6 dialup customers, but anyone on broadband will find your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload speed), then
you are on your way. Upload and download speeds are normally expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


Thanks for your answer Ron. I said in error download when I meant upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4 pages
per second simultaneously. Is that correct? If so, maybe that is enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have some
idea of the bandwidth requirements. In practice, some visitors will be
using broadband, some dialup, so there is some averaging to do here.
IMO 384kb is only suitable for a few simultaneous dialup customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message I am in the early stage of hosting my own sites on a Win 2003 server. I
know the general things in preparation for this but know nothing about
allocating enough bandwidth to insure that visitors are not slowed down
by my set up. I have checked everything as best I can but don't know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to be about
384kb down. Does anyone know a formula for determining the correct
amount based on the number of hits or visitors?
 
G

Guest

How much bandwidth is needed for roughly 20,000 visitors a month with an
averagr page size of 60kb?
Steve Easton said:
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

It is 384k bytes per second. Sorry if I confused anyone. This is another
new
area for me. Is my math correct that 6.4, 60kb pages could be downloaded
simutaneously per second then?


Ronx said:
Is that 384K bits or Bytes? If it's 384K bits then, as Jens remarked,
you
are not delivering as fast as I can download (512K bits/second). You
could serve 6 dialup customers, but anyone on broadband will find your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload speed),
then
you are on your way. Upload and download speeds are normally expressed
in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message Thanks for your answer Ron. I said in error download when I meant
upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4
pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast
as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have
some
idea of the bandwidth requirements. In practice, some visitors will
be
using broadband, some dialup, so there is some averaging to do here.
IMO 384kb is only suitable for a few simultaneous dialup customers -
and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003 server.
I
know the general things in preparation for this but know nothing
about
allocating enough bandwidth to insure that visitors are not slowed
down
by my set up. I have checked everything as best I can but don't know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to be
about
384kb down. Does anyone know a formula for determining the correct
amount based on the number of hits or visitors?
 
R

Ronx

That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around the
world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between 8am-6pm, no
repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your server will
handle this without problems. But is this the right scenario? And don't
forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


How much bandwidth is needed for roughly 20,000 visitors a month with an
averagr page size of 60kb?
Steve Easton said:
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

It is 384k bytes per second. Sorry if I confused anyone. This is another
new
area for me. Is my math correct that 6.4, 60kb pages could be downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens remarked,
you
are not delivering as fast as I can download (512K bits/second). You
could serve 6 dialup customers, but anyone on broadband will find your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload speed),
then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message Thanks for your answer Ron. I said in error download when I meant
upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4
pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast
as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have
some
idea of the bandwidth requirements. In practice, some visitors will
be
using broadband, some dialup, so there is some averaging to do here.
IMO 384kb is only suitable for a few simultaneous dialup customers -
and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know nothing
about
allocating enough bandwidth to insure that visitors are not slowed
down
by my set up. I have checked everything as best I can but don't know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to be
about
384kb down. Does anyone know a formula for determining the correct
amount based on the number of hits or visitors?
 
G

Guest

All visitors would probably be in the same time zone. They would visit at
peak times during consecutive 30 day periods. The 20000 would include repeat
visitors and each one may look at from 1-30 pages. The sites will consist of
roughly 350 pages with the avarge page size being 40kb.
You mentioned spiders which I haven't even thought about. Please give me an
alternative if you have one.

Ronx said:
That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around the
world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between 8am-6pm,
no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your server
will handle this without problems. But is this the right scenario? And
don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


How much bandwidth is needed for roughly 20,000 visitors a month with an
averagr page size of 60kb?
Steve Easton said:
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K bits/second). You
could serve 6 dialup customers, but anyone on broadband will find
your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload speed),
then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I meant
upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4
pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast
as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have
some
idea of the bandwidth requirements. In practice, some visitors
will be
using broadband, some dialup, so there is some averaging to do
here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits
per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know nothing
about
allocating enough bandwidth to insure that visitors are not slowed
down
by my set up. I have checked everything as best I can but don't
know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to be
about
384kb down. Does anyone know a formula for determining the correct
amount based on the number of hits or visitors?
 
S

Steve Easton

Here's some stats from a 300 page site with over 300 image files and some downloadable files in the
250kb range.

Visits Pages Files Hits
5777 17843 76760 90239

Bandwidth consumed month to date 354.88 Meg


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
........................with a computer

All visitors would probably be in the same time zone. They would visit at
peak times during consecutive 30 day periods. The 20000 would include repeat
visitors and each one may look at from 1-30 pages. The sites will consist of
roughly 350 pages with the avarge page size being 40kb.
You mentioned spiders which I haven't even thought about. Please give me an
alternative if you have one.

Ronx said:
That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around the
world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between 8am-6pm,
no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your server
will handle this without problems. But is this the right scenario? And
don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


How much bandwidth is needed for roughly 20,000 visitors a month with an
averagr page size of 60kb?
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K bits/second). You
could serve 6 dialup customers, but anyone on broadband will find
your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload speed),
then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I meant
upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4
pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as fast
as I
download, it is slow and will hold me up. Now multiply that by the
forecast number of simultaneous visitors to the sites and you have
some
idea of the bandwidth requirements. In practice, some visitors
will be
using broadband, some dialup, so there is some averaging to do
here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits
per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know nothing
about
allocating enough bandwidth to insure that visitors are not slowed
down
by my set up. I have checked everything as best I can but don't
know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to be
about
384kb down. Does anyone know a formula for determining the correct
amount based on the number of hits or visitors?
 
R

Ronx

What is a "peak time"? An hour each day, like rush hour? or two or three
days each month? or each week? Are all 20000 visitors going to arrive at
once like a plague of locusts?

Seriously, using my previous scenario coupled with the up to 30 pages for
each visitor, your server will have to cope with at least 15 pages per
minute, perhaps 45. If a "peak time" is one day each month, then that 15
ppm becomes 330-990ppm, or 5-16 pages per second (bandwidth required 200KB -
650KB). Your server will be working hard, but *might* just cope. But this
assumes the visitors are evenly spread over a ten hour day...
Also assumed is the 40KB page includes images and linked CSS and .js files.

Spiders turn up at all times of day and night, some go through every page,
some make several visits and spider a few pages at a time. They all return
at irregular intervals.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


All visitors would probably be in the same time zone. They would visit at
peak times during consecutive 30 day periods. The 20000 would include
repeat visitors and each one may look at from 1-30 pages. The sites will
consist of roughly 350 pages with the avarge page size being 40kb.
You mentioned spiders which I haven't even thought about. Please give me
an alternative if you have one.

Ronx said:
That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around the
world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between 8am-6pm,
no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your server
will handle this without problems. But is this the right scenario? And
don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


How much bandwidth is needed for roughly 20,000 visitors a month with an
averagr page size of 60kb?
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K bits/second).
You
could serve 6 dialup customers, but anyone on broadband will find
your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload
speed), then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I meant
upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4
pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as
fast as I
download, it is slow and will hold me up. Now multiply that by
the
forecast number of simultaneous visitors to the sites and you have
some
idea of the bandwidth requirements. In practice, some visitors
will be
using broadband, some dialup, so there is some averaging to do
here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits
per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know nothing
about
allocating enough bandwidth to insure that visitors are not slowed
down
by my set up. I have checked everything as best I can but don't
know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to be
about
384kb down. Does anyone know a formula for determining the correct
amount based on the number of hits or visitors?
 
G

Guest

I'm guessing peak time will be first, Fri-Sat 7-10 PM. Then, spread evenly
during the rest of the week. The 40kb would include all files. (I think this
is the normal time an average site is viewed.) These sites will be only
average. Nothing more even though I would like them to be something special.
Do you know of some software that would allow me to monitor all this?


Ronx said:
What is a "peak time"? An hour each day, like rush hour? or two or three
days each month? or each week? Are all 20000 visitors going to arrive at
once like a plague of locusts?

Seriously, using my previous scenario coupled with the up to 30 pages for
each visitor, your server will have to cope with at least 15 pages per
minute, perhaps 45. If a "peak time" is one day each month, then that 15
ppm becomes 330-990ppm, or 5-16 pages per second (bandwidth required
200KB - 650KB). Your server will be working hard, but *might* just cope.
But this assumes the visitors are evenly spread over a ten hour day...
Also assumed is the 40KB page includes images and linked CSS and .js
files.

Spiders turn up at all times of day and night, some go through every page,
some make several visits and spider a few pages at a time. They all
return at irregular intervals.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


All visitors would probably be in the same time zone. They would visit at
peak times during consecutive 30 day periods. The 20000 would include
repeat visitors and each one may look at from 1-30 pages. The sites will
consist of roughly 350 pages with the avarge page size being 40kb.
You mentioned spiders which I haven't even thought about. Please give me
an alternative if you have one.

Ronx said:
That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around the
world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between 8am-6pm,
no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your server
will handle this without problems. But is this the right scenario? And
don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message How much bandwidth is needed for roughly 20,000 visitors a month with
an averagr page size of 60kb?
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K bits/second).
You
could serve 6 dialup customers, but anyone on broadband will find
your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload
speed), then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I meant
upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4
pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as
fast as I
download, it is slow and will hold me up. Now multiply that by
the
forecast number of simultaneous visitors to the sites and you
have some
idea of the bandwidth requirements. In practice, some visitors
will be
using broadband, some dialup, so there is some averaging to do
here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits
per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know nothing
about
allocating enough bandwidth to insure that visitors are not
slowed down
by my set up. I have checked everything as best I can but don't
know
very much about the various providers and offerings they may have
currently. I want to start with enough bandwidth which seems to
be about
384kb down. Does anyone know a formula for determining the
correct
amount based on the number of hits or visitors?
 
R

Ronx

The server logs will monitor access. You may need a log analyser to assist,
such as Webalyser (spelling?).

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


I'm guessing peak time will be first, Fri-Sat 7-10 PM. Then, spread evenly
during the rest of the week. The 40kb would include all files. (I think
this is the normal time an average site is viewed.) These sites will be
only average. Nothing more even though I would like them to be something
special.
Do you know of some software that would allow me to monitor all this?


Ronx said:
What is a "peak time"? An hour each day, like rush hour? or two or three
days each month? or each week? Are all 20000 visitors going to arrive at
once like a plague of locusts?

Seriously, using my previous scenario coupled with the up to 30 pages for
each visitor, your server will have to cope with at least 15 pages per
minute, perhaps 45. If a "peak time" is one day each month, then that 15
ppm becomes 330-990ppm, or 5-16 pages per second (bandwidth required
200KB - 650KB). Your server will be working hard, but *might* just cope.
But this assumes the visitors are evenly spread over a ten hour day...
Also assumed is the 40KB page includes images and linked CSS and .js
files.

Spiders turn up at all times of day and night, some go through every
page, some make several visits and spider a few pages at a time. They
all return at irregular intervals.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


All visitors would probably be in the same time zone. They would visit
at peak times during consecutive 30 day periods. The 20000 would include
repeat visitors and each one may look at from 1-30 pages. The sites will
consist of roughly 350 pages with the avarge page size being 40kb.
You mentioned spiders which I haven't even thought about. Please give me
an alternative if you have one.

That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around
the world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many
pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between
8am-6pm, no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your server
will handle this without problems. But is this the right scenario?
And don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message How much bandwidth is needed for roughly 20,000 visitors a month with
an averagr page size of 60kb?
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K bits/second).
You
could serve 6 dialup customers, but anyone on broadband will find
your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload
speed), then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I meant
upload.
It is my upload speed that is 384kb. Not lets see if I can divide
correctly. At 60kb per page (average) visitors could download 6.4
pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as
fast as I
download, it is slow and will hold me up. Now multiply that by
the
forecast number of simultaneous visitors to the sites and you
have some
idea of the bandwidth requirements. In practice, some visitors
will be
using broadband, some dialup, so there is some averaging to do
here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K bits
per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know nothing
about
allocating enough bandwidth to insure that visitors are not
slowed down
by my set up. I have checked everything as best I can but don't
know
very much about the various providers and offerings they may
have
currently. I want to start with enough bandwidth which seems to
be about
384kb down. Does anyone know a formula for determining the
correct
amount based on the number of hits or visitors?
 
G

Guest

Thanks for all the help! One final question; will Webalyser show the
connection speed of a visitor and the download time for the pages that
visitor viewed?
Ronx said:
The server logs will monitor access. You may need a log analyser to
assist, such as Webalyser (spelling?).

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


I'm guessing peak time will be first, Fri-Sat 7-10 PM. Then, spread
evenly during the rest of the week. The 40kb would include all files. (I
think this is the normal time an average site is viewed.) These sites
will be only average. Nothing more even though I would like them to be
something special.
Do you know of some software that would allow me to monitor all this?


Ronx said:
What is a "peak time"? An hour each day, like rush hour? or two or
three days each month? or each week? Are all 20000 visitors going to
arrive at once like a plague of locusts?

Seriously, using my previous scenario coupled with the up to 30 pages
for each visitor, your server will have to cope with at least 15 pages
per minute, perhaps 45. If a "peak time" is one day each month, then
that 15 ppm becomes 330-990ppm, or 5-16 pages per second (bandwidth
required 200KB - 650KB). Your server will be working hard, but *might*
just cope. But this assumes the visitors are evenly spread over a ten
hour day...
Also assumed is the 40KB page includes images and linked CSS and .js
files.

Spiders turn up at all times of day and night, some go through every
page, some make several visits and spider a few pages at a time. They
all return at irregular intervals.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message All visitors would probably be in the same time zone. They would visit
at peak times during consecutive 30 day periods. The 20000 would
include repeat visitors and each one may look at from 1-30 pages. The
sites will consist of roughly 350 pages with the avarge page size being
40kb.
You mentioned spiders which I haven't even thought about. Please give
me an alternative if you have one.

That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around
the world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many
pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between
8am-6pm, no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your server
will handle this without problems. But is this the right scenario?
And don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message How much bandwidth is needed for roughly 20,000 visitors a month with
an averagr page size of 60kb?
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message
It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K bits/second).
You
could serve 6 dialup customers, but anyone on broadband will find
your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload
speed), then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I
meant upload.
It is my upload speed that is 384kb. Not lets see if I can
divide
correctly. At 60kb per page (average) visitors could download
6.4 pages
per second simultaneously. Is that correct? If so, maybe that is
enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as
fast as I
download, it is slow and will hold me up. Now multiply that by
the
forecast number of simultaneous visitors to the sites and you
have some
idea of the bandwidth requirements. In practice, some visitors
will be
using broadband, some dialup, so there is some averaging to do
here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K
bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know
nothing about
allocating enough bandwidth to insure that visitors are not
slowed down
by my set up. I have checked everything as best I can but don't
know
very much about the various providers and offerings they may
have
currently. I want to start with enough bandwidth which seems to
be about
384kb down. Does anyone know a formula for determining the
correct
amount based on the number of hits or visitors?
 
R

Ronx

The setup my host uses does not; I do not think that is an option.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


Thanks for all the help! One final question; will Webalyser show the
connection speed of a visitor and the download time for the pages that
visitor viewed?
Ronx said:
The server logs will monitor access. You may need a log analyser to
assist, such as Webalyser (spelling?).

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


I'm guessing peak time will be first, Fri-Sat 7-10 PM. Then, spread
evenly during the rest of the week. The 40kb would include all files. (I
think this is the normal time an average site is viewed.) These sites
will be only average. Nothing more even though I would like them to be
something special.
Do you know of some software that would allow me to monitor all this?


What is a "peak time"? An hour each day, like rush hour? or two or
three days each month? or each week? Are all 20000 visitors going to
arrive at once like a plague of locusts?

Seriously, using my previous scenario coupled with the up to 30 pages
for each visitor, your server will have to cope with at least 15 pages
per minute, perhaps 45. If a "peak time" is one day each month, then
that 15 ppm becomes 330-990ppm, or 5-16 pages per second (bandwidth
required 200KB - 650KB). Your server will be working hard, but *might*
just cope. But this assumes the visitors are evenly spread over a ten
hour day...
Also assumed is the 40KB page includes images and linked CSS and .js
files.

Spiders turn up at all times of day and night, some go through every
page, some make several visits and spider a few pages at a time. They
all return at irregular intervals.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message All visitors would probably be in the same time zone. They would visit
at peak times during consecutive 30 day periods. The 20000 would
include repeat visitors and each one may look at from 1-30 pages. The
sites will consist of roughly 350 pages with the avarge page size
being 40kb.
You mentioned spiders which I haven't even thought about. Please give
me an alternative if you have one.

That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around
the world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many
pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between
8am-6pm, no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your
server will handle this without problems. But is this the right
scenario? And don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message How much bandwidth is needed for roughly 20,000 visitors a month
with an averagr page size of 60kb?
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message
It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K bits/second).
You
could serve 6 dialup customers, but anyone on broadband will
find your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload
speed), then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I
meant upload.
It is my upload speed that is 384kb. Not lets see if I can
divide
correctly. At 60kb per page (average) visitors could download
6.4 pages
per second simultaneously. Is that correct? If so, maybe that
is enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload as
fast as I
download, it is slow and will hold me up. Now multiply that
by the
forecast number of simultaneous visitors to the sites and you
have some
idea of the bandwidth requirements. In practice, some
visitors will be
using broadband, some dialup, so there is some averaging to do
here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K
bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know
nothing about
allocating enough bandwidth to insure that visitors are not
slowed down
by my set up. I have checked everything as best I can but
don't know
very much about the various providers and offerings they may
have
currently. I want to start with enough bandwidth which seems
to be about
384kb down. Does anyone know a formula for determining the
correct
amount based on the number of hits or visitors?
 
G

Guest

Thanks again!
Ronx said:
The setup my host uses does not; I do not think that is an option.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


Thanks for all the help! One final question; will Webalyser show the
connection speed of a visitor and the download time for the pages that
visitor viewed?
Ronx said:
The server logs will monitor access. You may need a log analyser to
assist, such as Webalyser (spelling?).

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message I'm guessing peak time will be first, Fri-Sat 7-10 PM. Then, spread
evenly during the rest of the week. The 40kb would include all files.
(I think this is the normal time an average site is viewed.) These
sites will be only average. Nothing more even though I would like them
to be something special.
Do you know of some software that would allow me to monitor all this?


What is a "peak time"? An hour each day, like rush hour? or two or
three days each month? or each week? Are all 20000 visitors going to
arrive at once like a plague of locusts?

Seriously, using my previous scenario coupled with the up to 30 pages
for each visitor, your server will have to cope with at least 15 pages
per minute, perhaps 45. If a "peak time" is one day each month, then
that 15 ppm becomes 330-990ppm, or 5-16 pages per second (bandwidth
required 200KB - 650KB). Your server will be working hard, but
*might* just cope. But this assumes the visitors are evenly spread
over a ten hour day...
Also assumed is the 40KB page includes images and linked CSS and .js
files.

Spiders turn up at all times of day and night, some go through every
page, some make several visits and spider a few pages at a time. They
all return at irregular intervals.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message All visitors would probably be in the same time zone. They would
visit at peak times during consecutive 30 day periods. The 20000
would include repeat visitors and each one may look at from 1-30
pages. The sites will consist of roughly 350 pages with the avarge
page size being 40kb.
You mentioned spiders which I haven't even thought about. Please give
me an alternative if you have one.

That is a very difficult question to answer.
Are all the visitors in the same time zone, or equally spread around
the world?
Do they visit on weekends?
Do they sleep?
Does 20000 include repeat visits or are they unique?
Is 20000 pages served, or actual visitors? If visitors, how many
pages?

(Almost) Worst case (All visitors Mon-Fri evenly spread between
8am-6pm, no repeats, 20000 pages served, no pages refreshed)
20000pages/22days/10hours/60minutes=1.5 pages per minute. Your
server will handle this without problems. But is this the right
scenario? And don't forget search engine spiders.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
How much bandwidth is needed for roughly 20,000 visitors a month
with an averagr page size of 60kb?
In theory yes.


--
Steve Easton
Microsoft MVP FrontPage
95isalive
This site is best viewed............
.......................with a computer

<anon> wrote in message
It is 384k bytes per second. Sorry if I confused anyone. This is
another new
area for me. Is my math correct that 6.4, 60kb pages could be
downloaded
simutaneously per second then?


Is that 384K bits or Bytes? If it's 384K bits then, as Jens
remarked, you
are not delivering as fast as I can download (512K
bits/second). You
could serve 6 dialup customers, but anyone on broadband will
find your
server slow.

If its 384K Bytes per second (almost equivalent to 4Mb upload
speed), then
you are on your way. Upload and download speeds are normally
expressed in
bits per second.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
Thanks for your answer Ron. I said in error download when I
meant upload.
It is my upload speed that is 384kb. Not lets see if I can
divide
correctly. At 60kb per page (average) visitors could download
6.4 pages
per second simultaneously. Is that correct? If so, maybe that
is enough
to start and I could get more if necessary.


I do not know any formulae, but consider:
I download pages at 60KB/s[1] If your server cannot upload
as fast as I
download, it is slow and will hold me up. Now multiply that
by the
forecast number of simultaneous visitors to the sites and you
have some
idea of the bandwidth requirements. In practice, some
visitors will be
using broadband, some dialup, so there is some averaging to
do here.
IMO 384kb is only suitable for a few simultaneous dialup
customers - and
remember you are uploading, not downloading.

[1] 60KB/s (60K bytes per second) is roughly 512Kb/s (512K
bits per
second) with overheads.

--
Ron Symonds (Microsoft MVP - FrontPage)
Reply only to group - emails will be deleted unread.


<anon> wrote in message
I am in the early stage of hosting my own sites on a Win 2003
server. I
know the general things in preparation for this but know
nothing about
allocating enough bandwidth to insure that visitors are not
slowed down
by my set up. I have checked everything as best I can but
don't know
very much about the various providers and offerings they may
have
currently. I want to start with enough bandwidth which seems
to be about
384kb down. Does anyone know a formula for determining the
correct
amount based on the number of hits or visitors?
 
Top