Hi!
If it really is simple interest on each of the payments then you need:
=(60/2)*(24700*2.9%/12*60+24700+24700*2.9%/12*60+24700+59*-((24700*2.9
%/12*60+24700)-(24700*2.9%/12*59+24700)))
Returns: 1591235.75
Almost certainly capable of simplification but it's all based upon the
sum of an arithmetic progression. I haven't simplified because I'm not
sure that you really want simple interest and that is fairly rare
these days.
The first deposit of 24700 accumulates for 60 months at 2.9%/12 simple
interest.
This gives the first term of:
=24700*2.9%/12*60+24700
returns: 28281.5
The second deposit of 24700 accumulates for 59 months at 2.9%/12
simple interest
This gives the second term as:
=(24700*2.9%/12*59+24700)
returns: 28221.80833
The difference is -59.6916666666657
You could continue but you'll note a constant difference of -59.61
So we can sum the different amounts using:
Sn = n/2(t1+tn)
tn (the last term of the progression) is found using:
tn = t1+(n-1)d
=28281.5+(59*-59.69166667)
Returns: 24759.69
Putting that in the sum of arithmetic progression formula:
=60/2*(28281.5+24759.69)
Returns: 1591235.7
All the long formula above does is the string this into a single
formula.
With:
G1
24700
G2
2.9%
G3
60
Formula becomes:
=(G3/2)*(G1*G2/12*G3+G1+G1*G2/12*G3+G1+(G3-1)*-((G1*G2/12*G3+G1)-(G1*G
2/12*(G3-1)+G1)))
--
Regards
Norman Harker MVP (Excel)
Sydney, Australia
[email protected]
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