N
nobbyknownowt
Hi there all.
I have an equation as part of a long algorithm
a * cos (A) + (b-f) sin (A) - p * cos^2(A) = 0
The solution of which I need is A = 0
I have variables for a,b,f&p entered in cells (say a1,a2,a,3,a4) th
angle (A) could be between 0,90
Now then the result for say if a=1430 b=1651 f=7984 & p=600 would b
close to 7.5124035 (although that answer actually returns 0.0007670
and not 0)
I had originally thought it would be enough to run the equation in
spreadsheet with the variables in a box and then run the calculatio
900 times and vlookup the nearest to 0 bu0t have found that eve
withthe number setting set to no decimal places I need at least
decimal places. That would mean I would need to run the calculatio
900*900*900&^*&% alot of times.
I could round the number but then I'm likely to get more than on
answer.
Is there an easier way of doing this acurately without resorting t
lookup closest match???
cheers
Nobb
I have an equation as part of a long algorithm
a * cos (A) + (b-f) sin (A) - p * cos^2(A) = 0
The solution of which I need is A = 0
I have variables for a,b,f&p entered in cells (say a1,a2,a,3,a4) th
angle (A) could be between 0,90
Now then the result for say if a=1430 b=1651 f=7984 & p=600 would b
close to 7.5124035 (although that answer actually returns 0.0007670
and not 0)
I had originally thought it would be enough to run the equation in
spreadsheet with the variables in a box and then run the calculatio
900 times and vlookup the nearest to 0 bu0t have found that eve
withthe number setting set to no decimal places I need at least
decimal places. That would mean I would need to run the calculatio
900*900*900&^*&% alot of times.
I could round the number but then I'm likely to get more than on
answer.
Is there an easier way of doing this acurately without resorting t
lookup closest match???
cheers
Nobb