convert meters to feet/inches

[Ann]

i'm trying to convert from meters to feet and inches (not just feet or not
just inches).
so if i have 2 meters, i want the result to read 6 feet, 2 inches for
example not 6.x feet or 78 inches.
here's the formula i have, which i can't get right.
=CONVERT(2,"m","ft""in").
tia

 

[sb1920alk]

=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches"

Here I'm converting the value in A1 from meters to feet using 3.2808399 feet
per meter. The first part truncates the decimal protion and adds, "feet" and
the second part truncates the integer portion and convert it to inches and
adds "inches"

 

[JP]

One way:

Assume the # of meters is in A1:

To get feet, put this in B1:

=INT(CONVERT(A1,"m","ft"))

To get inches, put this in C1:

=ROUND(MOD(CONVERT(A13,"m","ft"),1)*12,1)


Put it together:

=B1&" feet and "&C1&" inches"


--JP

 

[JE McGimpsey]

One way:

=INT(CONVERT(A1,"m","ft")) & " feet, " &
TEXT(MOD(CONVERT(A1,"m","in"), 12), "0 ""inches""")

 

[Ann]

and if i was to reverse this formula? from feet and inches back to meters?
if feet is in a1 and inches is in b1
thanks guys

 

[sb1920alk]

=CONVERT(VALUE(SUBSTITUTE(A1," feet",""))+VALUE(SUBSTITUTE(B1,"
inches",""))/12,"ft","m")

 

[Ann]

thank you!!!

=CONVERT(VALUE(SUBSTITUTE(A1," feet",""))+VALUE(SUBSTITUTE(B1,"
inches",""))/12,"ft","m")

 

[sb1920alk]

I guess you don't need the Value function, so =CONVERT(SUBSTITUTE(A1,"
feet","")+SUBSTITUTE(B1," inches","")/12,"ft","m") would work too.

 

[David Biddulph]

Better to divide by 0.3048, rather than to multiply by what isn't exactly
the reciprocal.
Also, why are you using the strange ROUND construct, rather than using TRUNC
(or INT if the number is positive, as your ROUND only works for positive
numbers)?

Isn't =TRUNC(A1/0.3048)&" feet "&ROUND(MOD(A1/0.3048,1)*12,0)&" inches" a
bit easier than
=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches" ?

 

[David Biddulph]

Checking again in the negative number case, it does need something a bit
more complicated, such as:
=TRUNC(A1/0.3048)&" feet "&ABS(ROUND((A1/0.3048-TRUNC(A1/0.3048))*12,0))&"
inches"

 

[David Biddulph]

or (nearer to my earlier suggestion)
=TRUNC(A1/0.3048)&" feet "&ROUND(MOD(ABS(A1)/0.3048,1)*12,0)&" inches"

 

[sb1920alk]

Ok, you've sold me - I like TRUNC better now.

How often to you have a negative distance?

 

[Rick Rothstein \(MVP - VB\)]

Why not just this instead?

=TRUNC(A1/0.3048)&" feet "&ROUND(MOD(ABS(A1)/0.3048,1)*12,0)&" inches"

Rick

 

[TheBlueShadow]

I'm trying to put together a chart for track and field. This formula works
great except for one thing ... I'm wondering if you can find a solution.

If a pole vault bar is raised to 3.2 meters it equals 10' 6" like your
formula produces. But if the bar is raised to 3.35 meters the formula
produces 10' 12" ... is there a way to have the formula produce 11' instead?

Thank you.

 

[Glenn]

Change ROUND to TRUNC.

I'm trying to put together a chart for track and field. This formula works
great except for one thing ... I'm wondering if you can find a solution.

If a pole vault bar is raised to 3.2 meters it equals 10' 6" like your
formula produces. But if the bar is raised to 3.35 meters the formula
produces 10' 12" ... is there a way to have the formula produce 11' instead?

Thank you.

Why not just this instead?

=TRUNC(A1/0.3048)&" feet "&ROUND(MOD(ABS(A1)/0.3048,1)*12,0)&" inches"

Rick

Checking again in the negative number case, it does need something a bit
more complicated, such as:
=TRUNC(A1/0.3048)&" feet "&ABS(ROUND((A1/0.3048-TRUNC(A1/0.3048))*12,0))&"
inches"
--
David Biddulph

"David Biddulph" <groups [at] biddulph.org.uk> wrote in message
Better to divide by 0.3048, rather than to multiply by what isn't exactly
the reciprocal.
Also, why are you using the strange ROUND construct, rather than using
TRUNC (or INT if the number is positive, as your ROUND only works for
positive numbers)?

Isn't =TRUNC(A1/0.3048)&" feet "&ROUND(MOD(A1/0.3048,1)*12,0)&" inches" a
bit easier than
=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches" ?
--
David Biddulph

=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches"

Here I'm converting the value in A1 from meters to feet using 3.2808399
feet
per meter. The first part truncates the decimal protion and adds, "feet"
and
the second part truncates the integer portion and convert it to inches
and
adds "inches"

:

i'm trying to convert from meters to feet and inches (not just feet or
not
just inches).
so if i have 2 meters, i want the result to read 6 feet, 2 inches for
example not 6.x feet or 78 inches.
here's the formula i have, which i can't get right.
=CONVERT(2,"m","ft""in").
tia

 

[Glenn]

Although I'm not sure about your rounding rules.

You want 3.2 meters, which converts to 10 feet 5.98 inches to return 10 feet 6
inches.

You also want 3.35 meters, which converts to 10 feet 11.89 inches to return 10
feet 11 inches.

Under "normal" rounding rules, you would want 3.35 meters to result in 11 feet 0
inches. If that is what you really want, try this:

=INT(ROUND(CONVERT(A1,"m","in"),0)/12)&" feet "&
MOD(ROUND(CONVERT(A1,"m","in"),0),12)&" inches"

Change ROUND to TRUNC.

I'm trying to put together a chart for track and field. This formula
works great except for one thing ... I'm wondering if you can find a
solution.

If a pole vault bar is raised to 3.2 meters it equals 10' 6" like your
formula produces. But if the bar is raised to 3.35 meters the formula
produces 10' 12" ... is there a way to have the formula produce 11'
instead?

Thank you.

Why not just this instead?

=TRUNC(A1/0.3048)&" feet "&ROUND(MOD(ABS(A1)/0.3048,1)*12,0)&" inches"

Rick


"David Biddulph" <groups [at] biddulph.org.uk> wrote in message
Checking again in the negative number case, it does need something a
bit more complicated, such as:
=TRUNC(A1/0.3048)&" feet
"&ABS(ROUND((A1/0.3048-TRUNC(A1/0.3048))*12,0))&" inches"
--
David Biddulph

"David Biddulph" <groups [at] biddulph.org.uk> wrote in message
Better to divide by 0.3048, rather than to multiply by what isn't
exactly the reciprocal.
Also, why are you using the strange ROUND construct, rather than
using TRUNC (or INT if the number is positive, as your ROUND only
works for positive numbers)?

Isn't =TRUNC(A1/0.3048)&" feet "&ROUND(MOD(A1/0.3048,1)*12,0)&"
inches" a bit easier than
=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches" ?
--
David Biddulph

=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches"

Here I'm converting the value in A1 from meters to feet using
3.2808399 feet
per meter. The first part truncates the decimal protion and adds,
"feet" and
the second part truncates the integer portion and convert it to
inches and
adds "inches"

:

i'm trying to convert from meters to feet and inches (not just
feet or not
just inches).
so if i have 2 meters, i want the result to read 6 feet, 2 inches
for
example not 6.x feet or 78 inches.
here's the formula i have, which i can't get right.
=CONVERT(2,"m","ft""in").
tia

 

[David Biddulph]

To tackle that question, I would change my earlier formula (from more than a
year ago) to
=TRUNC(ROUND(A1/0.0254,0)/12)&" feet
"&ABS(ROUND(A1/0.0254,0)-TRUNC(ROUND(A1/0.0254,0)/12)*12)&" inches"

I will leave someone else to simplify it as Rick did for my previous effort.
--
David Biddulph

I'm trying to put together a chart for track and field. This formula works
great except for one thing ... I'm wondering if you can find a solution.

If a pole vault bar is raised to 3.2 meters it equals 10' 6" like your
formula produces. But if the bar is raised to 3.35 meters the formula
produces 10' 12" ... is there a way to have the formula produce 11'
instead?

Thank you.

Why not just this instead?

=TRUNC(A1/0.3048)&" feet "&ROUND(MOD(ABS(A1)/0.3048,1)*12,0)&" inches"

Rick

Checking again in the negative number case, it does need something a
bit
more complicated, such as:
=TRUNC(A1/0.3048)&" feet
"&ABS(ROUND((A1/0.3048-TRUNC(A1/0.3048))*12,0))&"
inches"
--
David Biddulph

"David Biddulph" <groups [at] biddulph.org.uk> wrote in message
Better to divide by 0.3048, rather than to multiply by what isn't
exactly
the reciprocal.
Also, why are you using the strange ROUND construct, rather than using
TRUNC (or INT if the number is positive, as your ROUND only works for
positive numbers)?

Isn't =TRUNC(A1/0.3048)&" feet "&ROUND(MOD(A1/0.3048,1)*12,0)&"
inches" a
bit easier than
=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches" ?
--
David Biddulph

=ROUND(A1*3.2808399-0.5,0)&" feet
"&ROUND((A1*3.2808399-ROUND(A1*3.2808399-0.5,0))*12,0)&" inches"

Here I'm converting the value in A1 from meters to feet using
3.2808399
feet
per meter. The first part truncates the decimal protion and adds,
"feet"
and
the second part truncates the integer portion and convert it to
inches
and
adds "inches"

:

i'm trying to convert from meters to feet and inches (not just feet
or
not
just inches).
so if i have 2 meters, i want the result to read 6 feet, 2 inches
for
example not 6.x feet or 78 inches.
here's the formula i have, which i can't get right.
=CONVERT(2,"m","ft""in").
tia

 

[matt]

One problem that I have while doing this is that I'd like the results to be
more precise.

I would like 12.35 meters to come out as 40' 6.25"

I'd even like to have the ' and " instead of feet/inches. Is all that a
possibility?

Thanks for help.

 

[David Biddulph]

=INT(A1*1000/(25.4*12))&"' "&ROUND(MOD(A1*1000/25.4,12),2)&""""

 

[Bill Sharpe]

=INT(A1*1000/(25.4*12))&"'"&ROUND(MOD(A1*1000/25.4,12),2)&""""

David's formula is precise, but it's going to show 6.22 inches rather
than 6.25 inches. 6.22, of course, is the correct answer to two decimal
places.
The convert function only works between two units of measurement, not
among three.

Bill