Different reply addresses

G

Gary

I was wondering if any kind soul could help me with this problem?

I use Outlook 2000 for my business and personal emails, so I would like to
be able to send an email to someone with one or the other email address on
it, for example the from line on a personal email could read
[email protected] and a business email which I sent to someone could
have an from line of [email protected]. I have checked the 2 email
accounts (for the 2 email addresses) and the personal account is set as
default at the minute.

I suspect that this problem has a really simple and obvious solution but
unfortunately it's just not simple or obvious enough for me.

All contributions gratefully accepted.

Gary
 
R

Russ Valentine [MVP-Outlook]

Not as simple as you might think, especially when you haven't provided us
enough information. You need to tell us which mail support mode of Outlook
2000 you are using. Line 2 of Help | About, if you don't know.
 
G

Gary

Sorted, thanks Russ

Russ Valentine said:
Should be simple then. IMO allows you to select the sending account on the
fly by clicking the arrow next to the Send button.

--
Russ Valentine
[MVP-Outlook]
Gary said:
Thanks Russ

It's set to internet mail only (if that helps?)

Gary

Russ Valentine said:
Not as simple as you might think, especially when you haven't provided us
enough information. You need to tell us which mail support mode of Outlook
2000 you are using. Line 2 of Help | About, if you don't know.

--
Russ Valentine
[MVP-Outlook]
I was wondering if any kind soul could help me with this problem?

I use Outlook 2000 for my business and personal emails, so I would
like
to
be able to send an email to someone with one or the other email
address
on
it, for example the from line on a personal email could read
[email protected] and a business email which I sent to someone
could
have an from line of [email protected]. I have checked the 2 email
accounts (for the 2 email addresses) and the personal account is set as
default at the minute.

I suspect that this problem has a really simple and obvious solution but
unfortunately it's just not simple or obvious enough for me.

All contributions gratefully accepted.

Gary
 
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