E
Ed
I have a folder on my FTP site that has documents that I wish to share with
others. I would like them to be able to simply click a button on a Word form
and the folder will open up. I recorded the following steps:
File|Open
(I then typed the following into the FileName box of the resulting dialog)
ftp://ftp.mysite.com/htdocs/ShareDoc/Docs/
(I then pressed Open and all files displayed.)
==========
All good so far.
I went to the macro editor and recovered the following code
ChangeFileOpenDirectory "ftp://ftp.mysite.com/htdocs/ShareDoc/Docs/"
I pasted the above code into a Sub attached to the button. When VBA runs the
line, I get an error 4172 (Path not found).
Is there a way to do this differently so it will work?
Thanks,
Ed
others. I would like them to be able to simply click a button on a Word form
and the folder will open up. I recorded the following steps:
File|Open
(I then typed the following into the FileName box of the resulting dialog)
ftp://ftp.mysite.com/htdocs/ShareDoc/Docs/
(I then pressed Open and all files displayed.)
==========
All good so far.
I went to the macro editor and recovered the following code
ChangeFileOpenDirectory "ftp://ftp.mysite.com/htdocs/ShareDoc/Docs/"
I pasted the above code into a Sub attached to the button. When VBA runs the
line, I get an error 4172 (Path not found).
Is there a way to do this differently so it will work?
Thanks,
Ed