Excel performance calculation

G

George

HI,
Could you let me know if there is an Excel function that calculates the
below formula:
List of percentages in column A, with the answer I want at the end of the
column is as follows:
[ (1+A1) x (1 +A2) x ...(1+An) ] -1
i have tried SumProduct but this does not work.
Thanks
George
 
G

George

Hi JE,
I am getting some errors can i send you an excel file for you to look at
exactly what i am trying to do?
George

JE McGimpsey said:
One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN):

=PRODUCT(1+A1:An)-1

George said:
HI,
Could you let me know if there is an Excel function that calculates the
below formula:
List of percentages in column A, with the answer I want at the end of the
column is as follows:
[ (1+A1) x (1 +A2) x ...(1+An) ] -1
i have tried SumProduct but this does not work.
Thanks
George
Click to expand...
Click to expand...
 
J

JE McGimpsey

I'd strongly suggest posting the errors you're getting, along with a
fuller description of what you're trying to do. If nothing else, it will
give a lot of other, perhaps smarter, folks a chance to help you, and
answer(s) in the archives may help someone else some day.

While this may not be the case with you, I find that when someone offers
to send a workbook rather than a description of the problem, it's almost
always the case that simply looking at the workbook isn't enough to
unambiguously decipher their intent. In addition, due to potential
virii, etc., I have to transfer such files to an isolated test machine
before opening them. So I accept such workbooks only at my usual spot
consulting rate (US$50/half-hour). Let me know.
 
G

George

No probs, understood.
Here is what i am trying to do:
Col a has a list of data / percentages
So cell b2 should equal (1+a2)*(1+a3)*(1+a4)-1
then cell b3 should equal (1+a3)*(1+a4)*(1+a5)-1
I tried "=PRODUCT(1+A2:A4)-1", but this does not equal the long formula above.
As i need to do this calc over a substantial amount of data, i really need a
function to assist.
Any help would be appreciated.
Thanks
George
 
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