FIND 2nd character in a string

[Fuzzy]

how do i use the FIND function to get the 2nd character?

for eg:

A1 has 005/0101/78445945/2002

the entire column has strings like the above....

i want only those characters after the 2nd "/" and before the 3rd "/"
what formula to use?

in the above result, the answer should be - 78445945

 

[pshepard]

Hi Fuzzy,

The Substitute function allows you to specify an instance # so that you can
identify where the 2nd instance of "/" is:

SUBSTITUTE(text,old_text,new_text,instance_num)

Substitute("\",a1,"unique character of your choice",2)

Then you can use Find:

Find("unique character of your choice",(substitute("\",a1,"unique character
of your choice",2),1)

Hope this helps.

Peggy

 

[Fuzzy]

Peggy - Thanks a ton!!!! Was simple and worked!!
Btw, the syntax for substitute was slightly wrong...
Correct - Substitute(a1,'/',"unique character of your choice",2)

 

[Fuzzy]

Perfect!!!
It worked!! Thank you....

Was wondering how to get the second "/" in that mid formula....
Coz i had used the mid as well as the find formula... just dint know how to
get the 2nd "/"

God Bless!

 

[Fuzzy]

Thanks a ton... it took me some time to figure out the cumbersome formula...
but finally got it....

and nope, dint try the user defined function.....

 

[Fuzzy]

The formula was complicated! but it worked!

Thank you very much.