Find latest value in a series.

  • Thread starter Mattlynn via OfficeKB.com
  • Start date
M

Mattlynn via OfficeKB.com

Hi
I have 4 rows of data.
Row 1 = Months of the year, Jan, Feb etc
Row 2 = target Values
Row 3 Actual Values
Row 4 Amber Values (vary between 80-90% of target)

I am creating a graph on separate tab and as a summary would like to bring
back the latest value on each row.
So if i complete for July, the summary will show me Target Actual and Amber
in 3 diff cells next to graph for July. If i plug in Aug data, the summary
changes to that data.

I have had a play with various methids, but cant cracki t.
Hopefully i have explained ok for all,
Can anyone help?
Many Thanks
Matt
 
T

T. Valko

TM's formula will return the last (rightmost) numeric value from row 1.

If that's what you wanted then just change the range reference to suit your
application. For example:

=LOOKUP(1E100,Sheet1!D5:J5)

--
Biff
Microsoft Excel MVP


Mattlynn via OfficeKB.com said:
Hi teethless - sorry but i do not understand the formula suggestion you
have
given?
Thanks

Can you please explain?


Teethless said:
=LOOKUP(1E100,1:1)
Hi
I have 4 rows of data.
[quoted text clipped - 14 lines]
Many Thanks
Matt
 
M

Mattlynn via OfficeKB.com

Thats brillaint - Thanks T Valko and thanks teethless mama

T. Valko said:
TM's formula will return the last (rightmost) numeric value from row 1.

If that's what you wanted then just change the range reference to suit your
application. For example:

=LOOKUP(1E100,Sheet1!D5:J5)
Hi teethless - sorry but i do not understand the formula suggestion you
have
[quoted text clipped - 10 lines]
 
T

T. Valko

You're welcome!

--
Biff
Microsoft Excel MVP


Mattlynn via OfficeKB.com said:
Thats brillaint - Thanks T Valko and thanks teethless mama

T. Valko said:
TM's formula will return the last (rightmost) numeric value from row 1.

If that's what you wanted then just change the range reference to suit
your
application. For example:

=LOOKUP(1E100,Sheet1!D5:J5)
Hi teethless - sorry but i do not understand the formula suggestion you
have
[quoted text clipped - 10 lines]
Many Thanks
Matt

--
Matt Lynn

Message posted via OfficeKB.com
http://www.officekb.com/Uwe/Forums.aspx/excel-functions/200910/1
 

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