Formula to answer YES or No

[bagoood]

Hi-
I want to create a field that will give a "YES" or "No" if the number in CEll A1 is not 15 percent higher or lower than cell A2 "YES"

Thanks,
Paul

 

[Claus Busch]

Hi Paul,

Am Tue, 25 Mar 2014 09:53:05 -0700 (PDT) schrieb (e-mail address removed):

I want to create a field that will give a "YES" or "No" if the number in CEll A1 is not 15 percent higher or lower than cell A2 "YES"

try:
=IF(ABS(1-A1/A2)<=0.15,"Yes","No")


Regards
Claus B.

 

[bagoood]

Hi Paul,



Am Tue, 25 Mar 2014 09:53:05 -0700 (PDT) schrieb (e-mail address removed):






try:

=IF(ABS(1-A1/A2)<=0.15,"Yes","No")

Thanks for your response!

Do this give me 15% above or below the number or just equal to or less than?
this what i'm trying to accomplish

I have two sample number that come of two different Laboratory analyzers

C3=allowable BIAS (15%)

c6=1.21 DXA analyzer(sample 1)
d8=1.34 DXB analyzer(sample 1)
e8=%diff
F8= this in where i want know if the %diff is higher or lower than 15% if so say "NO" if Not it is acceptable range and "YES" will be acceptable for comparison

Thanks,
Paul

 

[Claus Busch]

Hi,

Am Tue, 25 Mar 2014 11:26:02 -0700 (PDT) schrieb (e-mail address removed):

Do this give me 15% above or below the number or just equal to or less than?
this what i'm trying to accomplish

both because of ABS

C3=allowable BIAS (15%)

c6=1.21 DXA analyzer(sample 1)
d8=1.34 DXB analyzer(sample 1)
e8=%diff
F8= this in where i want know if the %diff is higher or lower than 15% if so say "NO" if Not it is acceptable range and "YES" will be acceptable for comparison

Try in F8:
=IF(ABS(E8<=C3),"Yes","No")


Regards
Claus B.

 

[bagoood]

Hi-

I want to create a field that will give a "YES" or "No" if the number in CEll A1 is not 15 percent higher or lower than cell A2 "YES"



Thanks,

Paul

Claus,

Thanks for the help!

Don't seem to be working right, but may be what i have for the percentage of the difference formula

VAL= =IF(C8="","",(((C8-D8)/ABS(D8))))

c8=1.56
d8=1.86
e8=-16%
f8 = yes
b3=12%