Help with Function: date range

[Bre-x]

Public Function my_dates(the_date As Date) As Integer

Select Case the_date
Case Between "07/31/2005" And "08/01/2006"
my_dates = 2006
case Between "07/31/2006" And "08/01/2007"
my_dates = 2006
Case Else
my_date = 0
End Select

End Function

If try to use # i get the same error

Help!!

Thank you
Bre-x

 

[Bre-x]

Public Function my_dates(the_date As Date) As Integer

Select Case the_date

Case #7/31/2005# To #8/1/2006#
my_dates = 2006
Case #7/31/2006# To #8/1/2007#
my_dates = 2007
Case #7/31/2007# To #8/1/2008#
my_dates = 2008
Case #7/31/2008# To #8/1/2009#
my_dates = 2009
Case #7/31/2009# To #8/1/2010#
my_dates = 2009
Case Else
my_date = 0
End Select
End Function

Thank you!!!

 

[Wayne-I-M]

datefield > #12/34/5678# AND datefield < #10/98/7651#

 

[John... Visio MVP]

Public Function my_dates(the_date As Date) As Integer

Select Case the_date
Case Between "07/31/2005" And "08/01/2006"
my_dates = 2006
case Between "07/31/2006" And "08/01/2007"
my_dates = 2006
Case Else
my_date = 0
End Select

End Function

If try to use # i get the same error

Help!!

Thank you
Bre-x

Or you could simplify it to something like
my_Date = Year(DateAdd("d", 153, the_Date))


John... Visio MVP

 

[Beetle]

How about;

Public Function my_dates(the_date As Date) As Integer

If Month(the-date)>7 Then
my_dates = Year(the_date) + 1
Else
my_dates = Year(the_date)
end if

End Function

Then you won't have to keep adding new lines to your code every year

 

[John W. Vinson]

Public Function my_dates(the_date As Date) As Integer

Select Case the_date

Case #7/31/2005# To #8/1/2006#
my_dates = 2006
Case #7/31/2006# To #8/1/2007#
my_dates = 2007
Case #7/31/2007# To #8/1/2008#
my_dates = 2008
Case #7/31/2008# To #8/1/2009#
my_dates = 2009
Case #7/31/2009# To #8/1/2010#
my_dates = 2009
Case Else
my_date = 0
End Select
End Function

Thank you!!!

Public Function My_Dates(the_date As Date) As Integer
My_Dates = Year(DateAdd("m", 5, the_date)
End Function

will work in any year (even leap years). And it's one line.

 

[John... Visio MVP]

Public Function My_Dates(the_date As Date) As Integer
My_Dates = Year(DateAdd("m", 5, the_date)
End Function

will work in any year (even leap years). And it's one line.

A lot more elegant than my solution. You only have to know the number of
months left in the year rather than the number of days left in the year.

John... Visio MVP

 

[KenSheridan via AccessMonster.com]

Your function seems rather inconsistent. Firstly the date ranges overlap on
31 July/1 August; secondly it returns the same value for the two years 31
July 2008 to 1 August 2010. Did you mean to return 2010 in the last case?

For greater flexibility the following returns the accounting year in a format
such as 2009-10 by passing the date value, and the day and month when the
accounting year starts into the function:

Public Function AcctYear(DateVal As Date, MonthStart As Integer, DayStart As
Integer) As String

Dim dtmYearStart As Date

' get start of accounting year in year of date value
dtmYearStart = DateSerial(Year(DateVal), MonthStart, DayStart)

' if date value is before start of accounting year
' accounting year starts year previous to date's year,
' otherwise it starts with date's year
If DateVal < dtmYearStart Then
AcctYear = Year(DateVal) - 1 & Format(Year(DateVal) Mod 100, "-00")
Else
AcctYear = Year(DateVal) & Format((Year(DateVal) + 1) Mod 100, "-00")
End If

End Function

For the UK fiscal year traditionally starting 5 April for instance:

AcctYear([TheDate], 4, 5)

In your case it would be:

AcctYear([TheDate], 8, 1)

I'm assuming your year starts 1 August.

To return just the ending year you'd amend it to:

If DateVal < dtmYearStart Then
AcctYear = Year(DateVal)
Else
AcctYear = Year(DateVal) + 1
End If

and make the data type of the return value an integer number rather than a
string.

Ken Sheridan
Stafford, England