K
KHogwood-Thompson
Hi,
I have been trying to hide access and just display the form to the user, I
found a thread on this site and used the following function code:
Option Compare Database
Global Const SW_HIDE = 0
Global Const SW_SHOWNORMAL = 1
Global Const SW_SHOWMINIMIZED = 2
Global Const SW_SHOWMAXIMIZED = 3
Private Declare Function apiShowWindow Lib "user32" _
Alias "ShowWindow" (ByVal hwnd As Long, _
ByVal nCmdShow As Long) As Long
Function fSetAccessWindow(nCmdShow As Long)
'Usage Examples
'Maximize window:
' ?fSetAccessWindow(SW_SHOWMAXIMIZED)
'Minimize window:
' ?fSetAccessWindow(SW_SHOWMINIMIZED)
'Hide window:
' ?fSetAccessWindow(SW_HIDE)
'Normal window:
' ?fSetAccessWindow(SW_SHOWNORMAL)
'
Dim loX As Long
Dim loForm As Form
On Error Resume Next
Set loForm = Screen.ActiveForm
If Err <> 0 Then 'no Activeform
If nCmdShow = SW_HIDE Then
MsgBox "Cannot hide Access unless " _
& "a form is on screen"
Else
loX = apiShowWindow(hWndAccessApp, nCmdShow)
Err.Clear
End If
Else
If nCmdShow = SW_SHOWMINIMIZED And loForm.Modal = True Then
MsgBox "Cannot minimize Access with " _
& (loForm.Caption + " ") _
& "form on screen"
ElseIf nCmdShow = SW_HIDE And loForm.PopUp <> True Then
MsgBox "Cannot hide Access with " _
& (loForm.Caption + " ") _
& "form on screen"
Else
loX = apiShowWindow(hWndAccessApp, nCmdShow)
End If
End If
fSetAccessWindow = (loX <> 0)
End Function
The switchboard form that is called from the startup option is set as popup
and modal, when I use the open event to call the function I get the following
message:
Cannot hide Access unless a form is on screen
The switchboard form is only then displayed when I click on OK and Access is
still on display. Can anyone advise please?
I have been trying to hide access and just display the form to the user, I
found a thread on this site and used the following function code:
Option Compare Database
Global Const SW_HIDE = 0
Global Const SW_SHOWNORMAL = 1
Global Const SW_SHOWMINIMIZED = 2
Global Const SW_SHOWMAXIMIZED = 3
Private Declare Function apiShowWindow Lib "user32" _
Alias "ShowWindow" (ByVal hwnd As Long, _
ByVal nCmdShow As Long) As Long
Function fSetAccessWindow(nCmdShow As Long)
'Usage Examples
'Maximize window:
' ?fSetAccessWindow(SW_SHOWMAXIMIZED)
'Minimize window:
' ?fSetAccessWindow(SW_SHOWMINIMIZED)
'Hide window:
' ?fSetAccessWindow(SW_HIDE)
'Normal window:
' ?fSetAccessWindow(SW_SHOWNORMAL)
'
Dim loX As Long
Dim loForm As Form
On Error Resume Next
Set loForm = Screen.ActiveForm
If Err <> 0 Then 'no Activeform
If nCmdShow = SW_HIDE Then
MsgBox "Cannot hide Access unless " _
& "a form is on screen"
Else
loX = apiShowWindow(hWndAccessApp, nCmdShow)
Err.Clear
End If
Else
If nCmdShow = SW_SHOWMINIMIZED And loForm.Modal = True Then
MsgBox "Cannot minimize Access with " _
& (loForm.Caption + " ") _
& "form on screen"
ElseIf nCmdShow = SW_HIDE And loForm.PopUp <> True Then
MsgBox "Cannot hide Access with " _
& (loForm.Caption + " ") _
& "form on screen"
Else
loX = apiShowWindow(hWndAccessApp, nCmdShow)
End If
End If
fSetAccessWindow = (loX <> 0)
End Function
The switchboard form that is called from the startup option is set as popup
and modal, when I use the open event to call the function I get the following
message:
Cannot hide Access unless a form is on screen
The switchboard form is only then displayed when I click on OK and Access is
still on display. Can anyone advise please?