Julian date calculating normal date one day off

L

laralea

This is the query (part of it)

[Call Detail].[ORIG DATE], [M] & "/" & [D] & "/" & [Y] AS [Date of Call],
Month(Right([ORIG DATE],3)) AS M, Day(Right([ORIG DATE],3)) AS D, Left([ORIG
DATE],4) AS Y,

Date entered in table: ORIG Date 2005182

Query Result
Date of Call 6/30/2005
M 6
D 30
Y 2005

M,D,Y, thus Date of Call are all off 1 day. 6/30/2005 is day 181 - not 182

Any ideas?

Thanks!
 
M

MGFoster

laralea said:
This is the query (part of it)

[Call Detail].[ORIG DATE], [M] & "/" & [D] & "/" & [Y] AS [Date of Call],
Month(Right([ORIG DATE],3)) AS M, Day(Right([ORIG DATE],3)) AS D, Left([ORIG
DATE],4) AS Y,

Date entered in table: ORIG Date 2005182

Query Result
Date of Call 6/30/2005
M 6
D 30
Y 2005

M,D,Y, thus Date of Call are all off 1 day. 6/30/2005 is day 181 - not 182

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You're using Day() incorrectly. Day() just returns the day of the month
of the indicated date. Day(182) is looking at 6/30/1900. The correct
syntax for Day() is Day(date_value). E.g.:

Day(#6/30/2005#) = 30

To get the correct date from the [Orig Date]:

DateAdd("d",
Right([Orig Date],3)-1,
DateSerial(Left([Orig Date],4), 1, 1))

--
MGFoster:::mgf00 <at> earthlink <decimal-point> net
Oakland, CA (USA)

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M

Marshall Barton

laralea said:
This is the query (part of it)

[Call Detail].[ORIG DATE], [M] & "/" & [D] & "/" & [Y] AS [Date of Call],
Month(Right([ORIG DATE],3)) AS M, Day(Right([ORIG DATE],3)) AS D, Left([ORIG
DATE],4) AS Y,

Date entered in table: ORIG Date 2005182

Query Result
Date of Call 6/30/2005
M 6
D 30
Y 2005

M,D,Y, thus Date of Call are all off 1 day. 6/30/2005 is day 181 - not 182

You can not use the Month and Day functions on non-date
values. A raw number such you are using is converted to a
date as the number of days since 30 Dec 1899, which is not
at all what you want to do.

You can convert your "Julian" date to a legitimate date
value bu using the DateSerial function:

DateSerial(Left([ORIG DATE],4), 1, Right([ORIG DATE],3))
 
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