MS ACCESS 2003 Report + SQL

[A64+]

Im using a Report in MS ACCESS 2003. Ive 2 tables. One named 'Candiate_Table'
and the other named 'Votes_Table'.
'Candidate_Table' has the id of each candidates which are primary-keys.
'Vote_Table' contains votes obtained for all candidates.

My Report displays the total number of votes obtained by a candidate.

Now my problem arises. At the last page of the report i want to display the
average votes earned by a candidate. However, i can display the total no of
votes obtained by a particluar candidate with the help of 'Expression
Builder' (ie, by giving '=count(*)' ). But i cant display the average votes
obtained by a candidate.

The table 'Vote_Table' contains votes obtained by all the candidate.
So my average vote display equation should be something like this:
(total_individual_candidate_vote/total_all_candidate_vote)/100.

But how can i accomplish this.
Do ive to write subqueries?

Im a beginner.
Please give me a solution. Im running out of time.

Thnx, always

-- Sometimes, Difficult things are possible...

 

[NoodNutt]

G'day (Unknown/Un-Named person, you)

There's no need to be shy, It's always nice to have ones name up there so
when replying we have someone to whom we can identify the facts to.

Visit:
http://www.mvps.org/access/netiquette.htm

It has valuable insight into what everyone should do in these situations.

Now, to your problem:

eg if

Total_Individual_Candidate_Vote = 290
Total_All_Candidate_Vote = 28125
your result would = 1.03%

If it is Query based then it would be:

Candidate_Vote_Percentage:
(Total_Individual_Candidate_Vote/Total_All_Candidate_Vote)*100

or if it is an Unbound Control on your report then you would put this in the
ControlSource:

= (Total_Individual_Candidate_Vote/Total_All_Candidate_Vote)*100

HTH
Mark.

It's always great recieving feedback, you know, like thx, great, worked like
a charm, so we know we have made your life a little happier and less
complicated.