odd issue with a loop

J

Joseph Atie

For counter = 1 To scount
sstring = Cells(counter + 82, 2).Value
Sheets(sstring).Select
ActiveSheet.PageSetup.Zoom = 75
ActiveWindow.SelectedSheets.PrintOut Copies:=1, Collate:=True
Next counter

the above section of code works for the first iteration of the loop on the
second iteration it fails to give sstring a value.

is there something wrong with the code?

p.s the aim of the code is to print off a number of sheets
 
L

Leith Ross

Joseph said:
For counter = 1 To scount
sstring = Cells(counter + 82, 2).Value
Sheets(sstring).Select
ActiveSheet.PageSetup.Zoom = 75
ActiveWindow.SelectedSheets.PrintOut Copies:=1, Collate:=True
Next counter

the above section of code works for the first iteration of the loop o
the
second iteration it fails to give sstring a value.

is there something wrong with the code?

p.s the aim of the code is to print off a number of sheets

Hello Joseph,

Since the loop only runs once, that indicates the control value sCoun
is less than 1. You need to make sure the variable is initialize
before startingg the loop

--
Leith Ros

Sincerely,
Leith Ross

'The Code Cage' (http://www.thecodecage.com/
 
N

Nigel

You need to specify the value of scount before the loop, also the line

Cells(Counter + 82, 2).Value

Is not fully referenced, so as you change the sheet, you are referencing the
Activesheet with the above statement, that maybe what you want ? If not add
the name of the sheet with the data e.g.

Sheets("Table").Cells(Counter + 82, 2).Value
 
D

Dave Peterson

Just to add to Nigel's response:

It's better to qualify the ranges and not select the sheet:

For counter = 1 To scount
sstring = worksheets("table").Cells(counter + 82, 2).Value
with Sheets(sstring)
.PageSetup.Zoom = 75
.PrintOut Copies:=1, Collate:=True
end with
Next counter
 

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