Recognizing #VALUE! as a condition in an IF Function Argument

J

Jim J.

Is there some way to get #VALUE! recognized as one of the conditions of an IF
function argument? For example, if D3 shows #VALUE! (as the result of a
"value error"), then one could ask, =IF(D3=#VALUE!,"bark","bite") or possibly
=IF(D3="#VALUE!","bark","bite"), and the result would be "bark" (since D3
really does equal "#VALUE!").
 
R

Ron Coderre

Try this:

=IF(ISERROR(D3),"bark","bite")

Does that help?

***********
Regards,
Ron

XL2002, WinXP-Pro
 
N

N Harkawat

If you are only isolating for an error then this should do
=if(iserror(d3),"bark","bite")
However it will show "bark" for all instances of error like #N/A, #Div
 
H

Harlan Grove

N Harkawat wrote...
If you are only isolating for an error then this should do
=if(iserror(d3),"bark","bite")
However it will show "bark" for all instances of error like #N/A, #Div
Click to expand...
....

So why not give the OP specifically what he asked for?

=IF(COUNT(1/(ERROR.TYPE(D3)=3)),"bark","bite")
 
Top