Aris,
Their is no built in function for that job, but here's one that works...
=RIGHT(A1,LEN(A1)-FIND(CHAR(164),SUBSTITUTE(A1," ",
CHAR(164),LEN(A1)-LEN(SUBSTITUTE(A1," ",""))),1))
I used a ¤ as a character I thought would be uncommon, if you
need to change that, change the 164...
Semi explanation
LEN(A29)-LEN(SUBSTITUTE(A29," ","")) denote as A
A counts the number of spaces
SUBSTITUTE(A29," ",CHAR(164),A) denote as B
B substitutes the last space for a ¤
FIND(CHAR(164),B,1) i'll call this C from now on
C finds the place of the ¤
LEN(A29)-C finds the required length
=RIGHT(A1,LEN(A1)-C) pulls the req'd letters from the end
Dan E