Which historical year will offer the same weekday ... ?

E

Eric

Today is 16 Mar, 2007 (Friday), does anyone know which historical year will
offer 16 Mar on Friday? On the other words, which historical year will offer
the same weekday on 2007 for everyday?
Thank for any suggestions
Eric
 
F

Fred Smith

365 days per year divided by 7 days per week yields a year of 52 weeks and one
day. Therefore, in a normal year a day falling on a Friday this year will fall
on Thursday next year. Except in leap years, where there will be two days
difference.

So the same weekday will always be five or six years ago depending on how many
leap days there are in between.

Google 'perpetual calendar' and you'll quickly be able to see which years in the
century have the same days of the week configuration.
 
H

Hans Terkelsen

Eric said:
Today is 16 Mar, 2007 (Friday), does anyone know which historical year will
offer 16 Mar on Friday? On the other words, which historical year will offer
the same weekday on 2007 for everyday?
Thank for any suggestions
Eric

Hi Eric.

An easy general way to get the same weekday,
and weeknumbers american and ISO,
is to add 400 years to the date.
400 years is 20871 weeks, counting the various leap days,
and then the calendar repeats itself, if you don't consider easter.

So 16 Mar 1607 was also a Friday, if your calendar was gregorian then.

Excel has a discrepancy 1/1/1900 and 60 days forward,
1/1/1900 weekday isn't 1/1/2300 weekday in Excel, but it should be.
The 1/1/2300 ... weekdays are the correct ones.

Hope that was useful, Hans.
 
D

David Biddulph

No I meant 7 days, Dave. In a normal year a date will move by one day of
the week from year to year. In a leap year it moves by two days of the
week. 2001 is indeed six years ago, so the date moves by one day for each
of those 6 years, plus an extra day for the one leap year in that period,
hence the date moves by 7 days, so in other words it's back to the same day
of the week.

Q.E.D.
 
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