Need Help with Totaling

[CRBI]

I'm not even sure how to explain this. I have a membership database in which
I've created a form for the member's basic data-name, address, phone, etc.
Within that form is a subform that shows where they have made donations, how
much, the date of the donation, and if it were for anything specific---could
be simple membership, end of year donation, river revelry
participation.....various things. I have to create annual reports showing how
much money we have taken in this year in membership donations. I have already
writtent the query to pull this and created the report. Here's my problem:
Some members may have contributed more than once over the course of the year.
When the query (and subsequent) report pulls my data, it is going to show
more than one entry for a person who has. My boss wants me to have the
query/report show a total of the member's contributions, rather than each
contribution. I could probably spend some time figuring this out on my own,
but since I have a tight deadline I thought I might ask if anyone knows a
fairly simple way I could do this. Any help is appreciated!

 

[BruceM via AccessMonster.com]

You should be able to do this with a Totals query. In the query design grid,
create a query with the Contribution and MemberID fields. Click the sideways
M on the toolbar (I forget the name of the symbol). This should add a Total
row to the design grid. Select Group By for MemberID, and Sum for
Contirbution. You may be able to add other fields such as FirstName or
LastName (choose Group By for the added fields, but be sure the number of
records does not change from when you used just MemberID and Contribution).

 

[Steve]

A Totals query would be a simple way to do this. Create a query that shows
each member and each of his donations. Click on the Sigma button (looks like
a capital E) at the top of the screen. Under the member field, change Group
By to Sum.

Steve
(e-mail address removed)

 

[Steve]

oops!!

Under the donation field, change Group By to Sum. Leave Group By under the
Member field.

Steve